Calculate the total power usage

Hi,

I have a live power reading which is coming in every so many seconds in Kw. Is there a way to calculate the total usage over a day? Not sure if SUM() would just add up all the data points ?

would the best way to be maybe limit the amount of data points to 60 seconds and then divide the SUM () by 86400 (24hrs) or os there already a way of doing such sum in influx?

Thanks

Sy

Hello @bceyresy,
Welcome!
I suggest using the aggregate window function:

from(bucket: "my bucket")
  |> range(start:  -10d)
  |> filter(fn: (r) => r["_measurement"] == "my measurement")
  |> filter(fn: (r) => r["_field"] == "kWh")
  |> aggregateWindow(every: 1d, fn: sum, createEmpty: false)
  |> yield(name: "daily sum or total")

Are you familiar with SQL perchance?
The following might be helpful if so:

The best way to do this is to integrate your power data into hourly energy data (or 15-minute intervals if your utility gives you a report in that format) as a task, and put that into a separate bucket. I keep two tasks, one that runs every hour and one that is done every week in case information came in late-- the integral is the same, just the window covered:

option task = {name: "IotaIntegral-Hourly", cron: "0 * * * *", offset: 1m}

data = from(bucket: "Iotabucket2")
	|> range(start: -1h)
	|> filter(fn: (r) =>
		(r["_field"] == "Watts"))
	|> aggregateWindow(every: 1h, fn: (tables=<-, column) =>
		(tables
			|> integral(unit: 1h)
			|> map(fn: (r) =>
				({r with _value: r._value / 1000.0, _field: "kWh", units: "kWh"}))))

data
	|> to(bucket: "IotaHourly")